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Linking PDO name to a friendly name

AvalonAvalon Member Posts: 31

Hello. Given an autogenerated PCI device name in the \Device tree (e.g. \Device\NTPNP_PCI0019), how can can we determine a friendly name like the one shown in device manager (e.g. NVIDIA Quadro P520). The autogenerated name appears in device manager as device property "Physical Device Object name".

Comments

  • Doron_HolanDoron_Holan Member - All Emails Posts: 10,582

    What are you going to do with the friendly name once you have it in kernel mode? Friendly name as a unique ID is problematic, it can be localized per user's language and not necessarily as unique as you think it is.

    d
  • MBond2MBond2 Member Posts: 304

    as Doron says, unless you have a tightly controlled setup, don't try this. remember that even on a single machine, this might vary between one user and the next depending on their regional options

  • AvalonAvalon Member Posts: 31
    edited March 31

    I'm not using it for anything that needs to be unique, and other languages are no problem. It's for logging purposes, I want a friendlier name than the autogen'd name of this PDO to store in my log, even a non-understandable Chinese device name is better than PCI0019. Device manager is able to do this for PCI devices, any clue how?

  • Peter_Viscarola_(OSR)Peter_Viscarola_(OSR) Administrator Posts: 8,399

    The friendly name comes out of the INF. It’s based on the device class, IIRC, so it’s not unique on a per device basis at all. It’s a category name. There are SetupDiXxx functions that’ll allow you to retrieve it, though I can’t remember if you can easily go from the embedded Device Object name to the Friendly Name.

    Peter

    Peter Viscarola
    OSR
    @OSRDrivers

  • Doron_HolanDoron_Holan Member - All Emails Posts: 10,582
    One of the simplest strings that remains constant over reboots is a device interface symlink. If you are creating a device interface you already have one lying around ;).
    d
  • AvalonAvalon Member Posts: 31
    edited March 31

    Thanks Scott that's exactly what I needed. Otherwise I would have had to take the longer path of Peter's method.

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