That is a software interrupt and not a hardware interrupt. There will be no device that can be detected or serviced. Far too little information.
“Madhusudan Narayan” wrote in message news:xxxxx@ntdev…
You can try this.
You need to know(determine) the interrupt vector.
Suppose it is 0x53,
Now you can fake an interrupt using
__asm int 0x53
Note: you can’t use variable names with “int” instruction. you might prefer to use a switch statement.
regards,
Maddy
On 3/19/07, xxxxx@gmail.com wrote:
Walter oney Programming the Microsoft Windows Driver Model:
Chapter 5 The I/O Request Packet:
The “Standard Model” for IRP Processing:
The StartIo Routine $B!'(BIn fact, sometimes the easiest way to commence a new operation is to store some state information in your device extension and then fake an interrupt
But how to “fake an interrupt” ???
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